Write a program to display days in a calendar

 Write a program to display days in a calendar format of an entered month of year 2015.

#include<stdio.h>
#include<conio.h>
void main()
{
int m,h,i=1,a,j,b=1;
clrscr();
printf (“\n Enter Month Number of the Year 2015 : “);
scanf (“%d”,&m); /* Program for finding days of any month of 2015*/
switch(m)
{
 case 1 :
 a=5;
 j=31;
 break;
 case 2 :
 a=1;
 j=28;
 break;
 case 3 :
 a=1;
 j=31;
 break;
 case 4 :
 a=4;
 j=30;
 break;
 case 5 :
 a=6;
 j=31;
 break;
 case 6 :
 a=2;
 j=30;
 break;
case 7 :
 a=4;
 j=31;
 break;
 case 8 :
 a=7;
 j=31;
 break;
 case 9 :
 a=3;
 j=30;
 break;
 case 10 :
 a=5;
 j=31;
 break;
 case 11 :
 a=1;
 j=30;
 break;
 case 12 :
 a=3;
 j=31;
 break;
 default :
 printf (“\a\a Invalid Month”);
 exit();
 }
/* starting day is to be shown/adjusted as per calendar */
printf (“\n\n\n”);
printf (“\t\t\tMonth - %d - 2015\n\n”,m);
printf (“ SUN MON TUE WED THU FRI SAT\n\n”);
 switch (a)
 {
 case 1 :
 printf (“\t%d”,i);
 break;
 case 2 :
 printf (“\t\t%d”,i);
 break;
 case 3 :
 printf (“\t\t\t%d”,i);
 break;
 case 4 :
 printf (“\t\t\t\t%d”,i);
 break;
 case 5 :
 printf (“\t\t\t\t\t%d”,i);
 break;
case 6 :
 printf (“\t\t\t\t\t\t%d”,i);
 break;
 case 7 :
 printf (“\t\t\t\t\t\t\t%d”,i);
 break;
 }
 h=8-a; /* The starting day is subtracted from 8 */
 for (i=2;i<=h;i++) /* To display the first row */
 printf (“\t%d”,i);
 printf (“\n”);
 for (i=h+1; i<=j;i++) /* To continue with second row onwards */
 {
 if (b==8) /* To terminate the line after every week */
 {
 printf (“\n”);
 b=1;
 }
 printf (“\t%d”,i);
 b++;
 }
 getch();
}

OUTPUT:

Enter Month Number of the Year 2015: 2

Month – 2 – 2015

SUN MON TUE WED THU FRI SAT

 1 2 3 4 5 6 7

 8 9 10 11 12 13 14

15 16 17 18 19 20 21

22 23 24 25 26 27 28