C program using dynamic memory allocation to read numbers as input and display them in sorted order thereafter

Write a program using dynamic memory allocation to read numbers as input and display them in sorted order thereafter.

#include<stdio.h>
#include<malloc.h>
int main()
{
	int *ptr,*ptr1,n,a,b,temp;
	printf("Enter how many elements you want to store: ");
	scanf("%d",&n);
	ptr=(int *)malloc(sizeof(int)*n);
	ptr1=ptr;
	printf("Enter %d elements for Array : ",n);
	for(a=0;a<n;a++)
	{
		scanf("%d",ptr+a);
	}
	
	printf("\nElements of Array Before Sort : \n");
	for(a=0;a<n;a++)
	{
		printf("%d\t",*(ptr+a));
	}
	
	for(a=0;a<n;a++)
	{
		for(b=0;b<(n-1)-a;b++)
		{
			if(*(ptr+b)>*(ptr+b+1))
			{
				temp=*(ptr+b);
				*(ptr+b)=*(ptr+b+1);
				*(ptr+b+1)=temp;
			}
		}
	}
	printf("\nElements of Array After Sort : \n");
	for(a=0;a<n;a++)
	{
		printf("%d\t",*(ptr+a));
	}
	
	return 0;
}

Enter how many elements you want to store: 7

Enter 7 elements for Array : 4 7 2 9 6 1 8

Elements of Array Before Sort :

4       7       2       9       6       1       8

Elements of Array After Sort :

1       2       4       6       7       8       9