23
'2+3'
'23'
None of These
[3, 4, 5, 20, 5, 25, 1, 3]
[1, 3, 3, 4, 5, 5, 20, 25]
[3, 5, 20, 5, 25, 1, 3]
[1, 3, 4, 5, 20, 5, 25]
What will be the output of the following expression?
a = 2 b = 8 print(a|b ) print(a >> 1)
10 0
10 2
2 2
10 1
what is the output of the following code?
M=['b' *x for x in range(4)] print(M)
['', 'b', 'bb', 'bbb']
['b,'bb', "bbb', "bbbb']
['b','bb', bbb']
none of these
What is the output of the following?
print(max([1, 2, 3, 4.] [4, 5, 6], [7]))
[4,5, 6
[7]
[1, 2,3, 4]
7
What will be the output of the following?
print(sum(1,2,3))
error
6
1
3
What will be the output of the following Python code?
list1=[1,3] list2=list1 list1[0]=4 print(list2)
[1, 4]
[1,3, 4]
[4,3]
[1,3]
anywhere in between the file
End
beginning
second line of the file
What will be the output of the following code snippet?
d={3,4,5} for k in d: print(k)
{3, 4, 5},{3, 4, 5}, {3, 4, 5}
3 4 5
syntax error
None of the above
What will be the output of following statement ?
>>>"m"+"n1"
'm+nl'
'mn1'
'm n1'
'm'
list
set
tuple
dict
tuple1=(5,1,7,6,2) tuple1.pop(2) print(tuple1)
(5,1,6,2)
(5,1,7,6)
(5,1,7,6,2)
Error
list1.sum(5)
list1.add(5)
listl.append(5)
list1.addelement(5)
Which of the following will delete key-value pair for key="tiger" in dictionary?
dic={"lion":"'wild","tiger":"'wild",'cat":"domestic","dog":"domestic"}
del dic("tiger")
dic["tiger"].delete()
delete(dic.["tiger'])
del dic["tiger"]
d1={"abc":5,"def":6,"ghi":7} print(d1[0])
abc
5
{"abc":5}
count()
strip()
upper()
उपरोकà¥à¤¤ सà¤à¥€
getkeys ()
key()
keys()
None
del
remove
removeAll
None of these
list1.addEnd (5)
list1.addLast (5)
list1.append (5)
0
4
2
