Dictionary
Tuple
Set
List
{}
[]
<>
()
Appending
Concatenation
Deleting
Slicing
What is the output of following code
x = [1, 2, 3] print(x[1:10])
Error
[2, 3]
[1, 2, 3]
a = "Python" print(a[-4:-1])
tho
yth
hon
thoN
x = [10, 20, 30] print(x * 0)
[0, 0, 0]
[ ]
0
String
x = "HELLO" print(x[1:-1])
ELL
ELLO
HELL
LL
d = {1:"A", 2:"B", 1:"C"} print(d)
{1:'A',2:'B'}
{1:'C',2:'B'}
{1:'A',1:'C',2:'B'}
d = {} d[1] = "Python" d[2] = "Java" print(len(d))
1
2
a = [1,2,3] del a[1] print(a)
[1,2,3]
[1,3]
[2,3]
a = [5,2,3] print(a[5:])
None
5
a=[2,3,4,5] a.insert(3,1) print(a)
[3,2,3,4,5]
[2, 3, 4, 1, 5]
[2, 3,1, 4, 5]
[2, 3,3, 4, 5]
a=[1,2,3] a[::-1] print(a)
[3,2,1]
[2,1,3]
[3,1,2]
What will be the output?
a = [1, 2, 3] b = a b.append(4) print(a)
[1, 2, 3, 4]
[4]
What will be printed?
a = [1, 2, 3] print(a * 2)
[2, 4, 6]
[1, 2, 3, 1, 2, 3]
[1, 4, 9]
What will be the result?
a = [1, 2, 3] print(a[1:])
[1]
[1, 2]
a = [1, 2, 3] a.insert(1, 10) print(a)
[1, 10, 2, 3]
[10, 1, 2, 3]
[1, 2, 10, 3]
a = [[1, 2], [3, 4]] print(a[1][0])
3
4
What is the output?
a = [1, 2, 3] a.remove(2) print(a)
[1, 3]
